A force of 91 ± 3 N is applied to a mass of 7 ± 0.2 kg. What is the acceleration of the mass?

A = F/m = 91/7 = 13 m/s² Percentage uncertainty for force = (3/91) × 100 = 3.3% Percentage uncertainty for mass = (0.2/7) × 100 = 2.9% Total % uncertainty = 3.3% + 2.9% = 6.2% 6.2% of 13 m/s² = 0.8 m/s² Final acceleration = 13 ± 0.8 m/s²