Electrolysis of molten lead (II) bromide:

-The electrolyte in this reaction is PbBr₂. This will become Br- and Pb²+ ions. -The Pb will move towards the cathode since it is a negative ion where it will gain electrons -to form lead atoms. Half equation for the reaction at the cathode: -Pb²+(aq) + 2e- -> Pb(s) -The Br- will move towards the anode since it is a positive ion where it will lose electrons to -form bromide atoms. Half equation for the reaction at the anode: -2Br- -> Br₂ + 2e- -The overall reaction looks like this: -Pb²+ + 2Br- -> Pb +Br₂