Talk about the observed phenotype of dihybrid cross.

9:3:3:1 (9 dominant dominant, 3 dominant recessive for both, 1 recessive recessive) We can obtain it by the method (branched diagram) of showing the probabilities of each independently and multiplying them (P(A and B)= P(A) * P(B) for each recessive and dominant) (2^n total where n is the number of total alleles.)